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Post by milliondollarsav on Jul 4, 2015 20:41:33 GMT -5
I have this one idea for an event that all Millionaire shows can be involved in. What if all the millionaires (or the highest winning players) from each international version all compete for 10 million dollars (or the equivalent currency for other international versions). I'm not sure if this can be even possible. One reason why is because some international versions don't have contestants who speak English or other languages. Although this might not happen, at least you can tell me what else is wrong with it. The title is another thing that needs work.
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OMDolton99
My thoughts are with everyone affected by the #ParisAttacks. Isis need to be eliminated. NOW.
Posts: 285
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Post by OMDolton99 on Jul 6, 2015 10:32:22 GMT -5
That sounds similar to the "Tournament of Ten" they did on the American version during the Clock era. How would you run it? Would the top player be guaranteed the $10M or would only the top player get their prize?
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Post by milliondollarsav on Jul 6, 2015 11:50:58 GMT -5
I don't think it would be like the Tournament of Ten. I was thinking of something way different. The tournament would be a "bracket format". Each player will compete in a duel similar to the final round of "The Weakest Link" where the player with the most right answers will move on. If a tie occurs, a Fastest Finger question will be played. All players can use 3 lifelines for the whole tournament. In the finals, the 2 players would only answer 1 question with no lifelines. The player who correctly answers the question the fastest wins the tournament.
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Post by kplewisvox on Jul 6, 2015 12:11:18 GMT -5
I mentioned something like this once. You could even limit it to English speaking countries with more than one top winner. Get two top winners from the US, England, Australia and India. Eight players is enough for a special week of shows. Fly them to the UK, let them play FF, and let them play for £1 million in normal play (no tournament). Bring the four hosts as well, and have them round-robin.
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